Finding the Square root of a given number using both manual and Java inbuilt functionality

Hi All,

Here I write programs for finding the Square root of a given number using both manual and Java inbuilt functionality :-)

 

import java.util.Scanner;

public class squareRoot {
    public static void main(String args[]) {
        System.out.println("SquareRoot in Java ");       
        Scanner scanner = new Scanner(System.in);
        System.out.println("Enter number to find square root: ");       
        double square = scanner.nextDouble(); //Reading value from console
        double squareRoot = Math.sqrt(square);    // Java inbuilt functionality for squareRoot the given number
        System.out.println("Square root of Given number: " + square + " is -> " + squareRoot);
         System.out.println("");
        
        //Manually calculating SquareRoot of given number 
        System.out.println("Enter number to find square root: ");      
        double square1 = scanner.nextDouble();
        manuallySquare(square1);
    }
    public static void manuallySquare(double square) {
        double x = 1;
        for (int i = 0; i < square; i++) {
            x = 0.5 * (x + square / x);
        }
        System.out.println("Square root of Given number: " + square + " is: -> " + x);
    }
}

Output:

~~~~~~

SquareRoot in Java
Enter number to find square root:
25
Square root of Given number: 25.0 is -> 5.0

Enter number to find square root:
64
Square root of Given number: 64.0 is: -> 8.0